Hey guys,

Since I started learning and reading about breeding, I have been taking a lot of time doing punnett squares. Everyday I do a couple to look at possible combinations I can produce in the next few years. I have to say, some of my friends and co-workers are getting weirded out because I talk about snakes all the time now, haha.

So I have figured out everything up to the 1/16 odds punnett squares. That is to say everything that is 4-gene or less. Here are a few examples (I want to see if I am doing it right)

p = pastel, P = normal gene
s = spider, S = normal gene
q = lesser, Q = normal gene (i use Q's becuase L's are hard to read)

Lesser Pastel (qQpP) x Bumble Bee (pPsS)


So that gives:
1/16 Killer Queen Bee
1/16 Super Pastel Lesser
1/16 Killer Bee
2/16 Queen Bee
1/16 Super Pastel
2/16 Bumble Bee
2/16 Pastel Lesser
1/16 Lesser Spider
2/16 Pastel
1/16 Lesser
1/16 Spider
1/16 Normal

So I'm pretty sure thats correct. Now trying to understand recessive genes.

p = pastel, P = normal gene
b = piebald, B = normal gene (needs two "b"'s for visual morph)
a = albino, A = normal gene (needs two "a"'s for visual morph)

Pastel Piebald (pPbb) x Albino (aa):


Offspring would be:
1/2 Pastel 100% Double Het Albino Piebald
1/2 Normal 100% Double Het Albino Piebald

Here is my million dollar question. Somebody who knows this stuff help me out if you can

How do you calculate, in terms of punnett squares, this pairing:

Pastel 100% Double Het Albino Pied x Pastel 100% Double Het Albino Pied??

I know for a fact there is a 1/64 chance for Killer Pied Albino, because Jkobylka talks about it at some point in his videos. But I am really clueless as to how to setup a 8 by 8 punnett square. Someone help !