Het. question

[lance]

So this may be a good question or u may be like wow is this guy retarded, the question is say I have a het. albino and breed it to a normal what is the odds of having and albino morph?

thanks kindly,

Lance

[771subliminal]

So this may be a good question or u may be like wow is this guy retarded, the question is say I have a het. albino and breed it to a normal what is the odds of having and albino morph?

thanks kindly,

Lance

0%

albino is recessive both parents have to pass on the albino gene in order to make a albino.

het albino x normal=
50% WT
50% Het. albino,

het albino x het albino =
25% WT
50% Het. albino,
25% Homozygous albino

het albino x albino =
50% Het. albino,
50% Homozygous albino

albino x albino
100% albinos

[lance]

0%

albino is recessive both parents have to pass on the albino gene in order to make a albino.

het albino x normal=
50% WT
50% Het. albino,

het albino x het albino =
25% WT
50% Het. albino,
25% Homozygous albino

het albino x albino =
50% Het. albino,
50% Homozygous albino

albino x albino
100% albinos

what would you get with a Male het lavendar and and albino or normal?

thanks kindly

lance

[Gavin Cooper]

what would you get with a Male het lavender and and albino or normal?

thanks kindly

lance

You run into the same problem here. For one the het Lav and Albino are not compatible and therefore you will only get 50% het Lavs and 50% het Lavs, het Albino. But without being able to tell which are DH and which are just het Lav it would be a waste of time. You would have a whole clutch of poss DH Lav/Albino.

And with the het Lav to normal is exactly the same odds as the het Albino x Normal in your first post.
0% chance of visuals.
50% het Lavs
50% Normals
= Clutch of possible het Lavs.

Both animals need to have the same compatible recessive gene to produce anything visual.


Gavin

[qinw]

Wt = ??

[OhhWatALoser]

without trait

[BAMReptiles]

without trait

wt means wild type, ive never heard it mean without trait

[Gavin Cooper]

wt means wild type, ive never heard it mean without trait

x2

Wild type or aka Normal


Gavin

[angllady2]

The whole genetic thing is still really confusing.

I do know that all recessive genes mean you need two copies of the gene, one from each snake, to produce a visual.

Co Dominant genes mean you only need one gene to get more, since the snake is visual, it's easy to tell these. Any babies from a co-dom will be statistically half morph and half normal.

There are a few dominant out there as well, where having one visual snake bred to anything will produce nothing but more of the morph.

So far the recessive genes I know of are these:

Albino
Axanthic
Caramel
Clown
Genetic Stripe
Ghost
Lavender
Piebald


Co doms I know of are:

Black Pastel
Butter
Calico
Champagne
Cinnamon
Enchi
Fire
Lesser
Mojave
Pastel
Phantom
Pinstripe
Spector
Spider
Spotnose
Vanilla
Woma
Yellowbelly


I'm sure there are others. True dominant genes I'm not sure about, besides super forms of co-doms.

Gale

[abi21491]

There are a few dominant out there as well, where having one visual snake bred to anything will produce nothing but more of the morph.

Dominant genes don't produce 100% morphs - it's still a 50/50 of getting the morph or the normal. Pinstripe is dominant, Pinstripe x normal would be 50/50 approximately. Unless of course you're talking about a Pinstripe that is homozygous (has 2 pin genes), in that case it would produce 100% pinstripes